Base | Representation |
---|---|
bin | 10011010111100111101… |
… | …000011110000000101001 |
3 | 11201020121211201121122110 |
4 | 103113213220132000221 |
5 | 133301422421240131 |
6 | 2455244530312533 |
7 | 165110122111023 |
oct | 23274750360051 |
9 | 4636554647573 |
10 | 1331031040041 |
11 | 47353a35a92a |
12 | 195b67728749 |
13 | 98691c76bb1 |
14 | 485ca901013 |
15 | 24953312646 |
hex | 135e7a1e029 |
1331031040041 has 32 divisors (see below), whose sum is σ = 1826607138048. Its totient is φ = 861509468160.
The previous prime is 1331031040039. The next prime is 1331031040099. The reversal of 1331031040041 is 1400401301331.
It is not a de Polignac number, because 1331031040041 - 21 = 1331031040039 is a prime.
It is a super-2 number, since 2×13310310400412 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1331031044041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 210038025 + ... + 210044361.
It is an arithmetic number, because the mean of its divisors is an integer number (57081473064).
Almost surely, 21331031040041 is an apocalyptic number.
It is an amenable number.
1331031040041 is a deficient number, since it is larger than the sum of its proper divisors (495576098007).
1331031040041 is a wasteful number, since it uses less digits than its factorization.
1331031040041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10161.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1331031040041 its reverse (1400401301331), we get a palindrome (2731432341372).
The spelling of 1331031040041 in words is "one trillion, three hundred thirty-one billion, thirty-one million, forty thousand, forty-one".
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