Base | Representation |
---|---|
bin | 11110010000111011000011… |
… | …110101100110111110001111 |
3 | 122110021122112001202000110120 |
4 | 132100323003311212332033 |
5 | 114421240122430112143 |
6 | 1151031140442240023 |
7 | 40015320120251043 |
oct | 3620730365467617 |
9 | 573248461660416 |
10 | 133104322113423 |
11 | 394582538a0871 |
12 | 12b186141b6013 |
13 | 59368b718738b |
14 | 24c23d8158023 |
15 | 105c5376c8383 |
hex | 790ec3d66f8f |
133104322113423 has 4 divisors (see below), whose sum is σ = 177472429484568. Its totient is φ = 88736214742280.
The previous prime is 133104322113383. The next prime is 133104322113443. The reversal of 133104322113423 is 324311223401331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133104322113423 - 213 = 133104322105231 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133104322113443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22184053685568 + ... + 22184053685573.
It is an arithmetic number, because the mean of its divisors is an integer number (44368107371142).
Almost surely, 2133104322113423 is an apocalyptic number.
133104322113423 is a deficient number, since it is larger than the sum of its proper divisors (44368107371145).
133104322113423 is an equidigital number, since it uses as much as digits as its factorization.
133104322113423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44368107371144.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 133104322113423 its reverse (324311223401331), we get a palindrome (457415545514754).
The spelling of 133104322113423 in words is "one hundred thirty-three trillion, one hundred four billion, three hundred twenty-two million, one hundred thirteen thousand, four hundred twenty-three".
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