13311001121 has 4 divisors (see below), whose sum is σ = 14521092144. Its totient is φ = 12100910100.

The previous prime is 13311001111. The next prime is 13311001141. The reversal of 13311001121 is 12110011331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12110011331 = 11 ⋅1100910121.

It is a cyclic number.

It is not a de Polignac number, because 13311001121 - 2²² = 13306806817 is a prime.

It is a super-3 number, since 3×13311001121³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311001096 and 13311001105.

It is not an unprimeable number, because it can be changed into a prime (13311001111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605045495 + ... + 605045516.

It is an arithmetic number, because the mean of its divisors is an integer number (3630273036).

Almost surely, 2^13311001121 is an apocalyptic number.

13311001121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13311001121 is a deficient number, since it is larger than the sum of its proper divisors (1210091023).

13311001121 is a wasteful number, since it uses less digits than its factorization.

13311001121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1210091022.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 13311001121 its reverse (12110011331), we get a palindrome (25421012452).

The spelling of 13311001121 in words is "thirteen billion, three hundred eleven million, one thousand, one hundred twenty-one".