Base | Representation |
---|---|
bin | 1100000110110011011000… |
… | …1101101100110100110001 |
3 | 1202010112001101201122221122 |
4 | 3001230312031230310301 |
5 | 3221041423340231231 |
6 | 44150554533032025 |
7 | 2542455213313151 |
oct | 301546615546461 |
9 | 52115041648848 |
10 | 13311013211441 |
11 | 4272194a38830 |
12 | 15ab91b485615 |
13 | 7572b9388b8a |
14 | 340383ab6761 |
15 | 1813b3b4477b |
hex | c1b3636cd31 |
13311013211441 has 4 divisors (see below), whose sum is σ = 14521105321584. Its totient is φ = 12100921101300.
The previous prime is 13311013211429. The next prime is 13311013211453. The reversal of 13311013211441 is 14411231011331.
It is a happy number.
13311013211441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (13311013211429) and next prime (13311013211453).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13311013211441 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13311013211441.
It is not an unprimeable number, because it can be changed into a prime (13311013211341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605046055055 + ... + 605046055076.
It is an arithmetic number, because the mean of its divisors is an integer number (3630276330396).
Almost surely, 213311013211441 is an apocalyptic number.
13311013211441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13311013211441 is a deficient number, since it is larger than the sum of its proper divisors (1210092110143).
13311013211441 is a wasteful number, since it uses less digits than its factorization.
13311013211441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1210092110142.
The product of its (nonzero) digits is 864, while the sum is 26.
Adding to 13311013211441 its reverse (14411231011331), we get a palindrome (27722244222772).
The spelling of 13311013211441 in words is "thirteen trillion, three hundred eleven billion, thirteen million, two hundred eleven thousand, four hundred forty-one".
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