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1331111031322 = 2665555515661
BaseRepresentation
bin10011010111101100011…
…001100111001000011010
311201020211102020121001111
4103113230121213020122
5133302103411000242
62455300505010534
7165112113036532
oct23275431471032
94636742217044
101331111031322
11473580525526
12195b8a483a4a
13986a5703307
14485d73a44c2
152495a363817
hex135ec66721a

1331111031322 has 4 divisors (see below), whose sum is σ = 1996666546986. Its totient is φ = 665555515660.

The previous prime is 1331111031301. The next prime is 1331111031329. The reversal of 1331111031322 is 2231301111331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1096981822161 + 234129209161 = 1047369^2 + 483869^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1331111031293 and 1331111031302.

It is not an unprimeable number, because it can be changed into a prime (1331111031329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332777757829 + ... + 332777757832.

Almost surely, 21331111031322 is an apocalyptic number.

1331111031322 is a deficient number, since it is larger than the sum of its proper divisors (665555515664).

1331111031322 is an equidigital number, since it uses as much as digits as its factorization.

1331111031322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 665555515663.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1331111031322 its reverse (2231301111331), we get a palindrome (3562412142653).

The spelling of 1331111031322 in words is "one trillion, three hundred thirty-one billion, one hundred eleven million, thirty-one thousand, three hundred twenty-two".

Divisors: 1 2 665555515661 1331111031322