1331112201101 has 4 divisors (see below), whose sum is σ = 1331114901600. Its totient is φ = 1331109500604.

The previous prime is 1331112201079. The next prime is 1331112201103. The reversal of 1331112201101 is 1011022111331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1331112201101 is a prime.

It is a super-2 number, since 2×1331112201101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1331112201101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331112201103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 377081 + ... + 1674638.

It is an arithmetic number, because the mean of its divisors is an integer number (332778725400).

Almost surely, 2^{1331112201101} is an apocalyptic number.

It is an amenable number.

1331112201101 is a deficient number, since it is larger than the sum of its proper divisors (2700499).

1331112201101 is an equidigital number, since it uses as much as digits as its factorization.

1331112201101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2700498.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1331112201101 its reverse (1011022111331), we get a palindrome (2342134312432).

The spelling of 1331112201101 in words is "one trillion, three hundred thirty-one billion, one hundred twelve million, two hundred one thousand, one hundred one".