13311140010433 has 8 divisors (see below), whose sum is σ = 13555922341248. Its totient is φ = 13067713815024.

The previous prime is 13311140010431. The next prime is 13311140010439. The reversal of 13311140010433 is 33401004111331.

13311140010433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13311140010433 - 2¹ = 13311140010431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311140010398 and 13311140010407.

It is not an unprimeable number, because it can be changed into a prime (13311140010431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 339014041 + ... + 339053302.

It is an arithmetic number, because the mean of its divisors is an integer number (1694490292656).

Almost surely, 2^{13311140010433} is an apocalyptic number.

It is an amenable number.

13311140010433 is a deficient number, since it is larger than the sum of its proper divisors (244782330815).

13311140010433 is an equidigital number, since it uses as much as digits as its factorization.

13311140010433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 678067703.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13311140010433 its reverse (33401004111331), we get a palindrome (46712144121764).

The spelling of 13311140010433 in words is "thirteen trillion, three hundred eleven billion, one hundred forty million, ten thousand, four hundred thirty-three".