Base | Representation |
---|---|
bin | 111101111111000010… |
… | …0001111110101110011 |
3 | 110201120202212010012202 |
4 | 1323332010033311303 |
5 | 4140103023421303 |
6 | 141052310213415 |
7 | 12421425315500 |
oct | 1737604176563 |
9 | 421522763182 |
10 | 133111545203 |
11 | 514a7aa709a |
12 | 2196a95426b |
13 | c724712840 |
14 | 662a82a4a7 |
15 | 36e10dcc88 |
hex | 1efe10fd73 |
133111545203 has 24 divisors (see below), whose sum is σ = 172134345600. Its totient is φ = 101921621760.
The previous prime is 133111545199. The next prime is 133111545221. The reversal of 133111545203 is 302545111331.
It is not a de Polignac number, because 133111545203 - 22 = 133111545199 is a prime.
It is a super-2 number, since 2×1331115452032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133111548203) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3350678 + ... + 3390171.
It is an arithmetic number, because the mean of its divisors is an integer number (7172264400).
Almost surely, 2133111545203 is an apocalyptic number.
133111545203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
133111545203 is a deficient number, since it is larger than the sum of its proper divisors (39022800397).
133111545203 is a wasteful number, since it uses less digits than its factorization.
133111545203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6740907 (or 6740900 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 133111545203 its reverse (302545111331), we get a palindrome (435656656534).
The spelling of 133111545203 in words is "one hundred thirty-three billion, one hundred eleven million, five hundred forty-five thousand, two hundred three".
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