Base | Representation |
---|---|
bin | 11110010001000010001101… |
… | …011110110011011111110111 |
3 | 122110022101100011020011110111 |
4 | 132101002031132303133313 |
5 | 114421401334011202333 |
6 | 1151034450400203451 |
7 | 40016011311126415 |
oct | 3621021536633767 |
9 | 573271304204414 |
10 | 133112000100343 |
11 | 3946053391a000 |
12 | 12b19bb7609587 |
13 | 593753ba92bc4 |
14 | 24c2925b5c2b5 |
15 | 105c8367b74cd |
hex | 79108d7b37f7 |
133112000100343 has 16 divisors (see below), whose sum is σ = 146485433652480. Its totient is φ = 120951207219480.
The previous prime is 133112000100341. The next prime is 133112000100407. The reversal of 133112000100343 is 343001000211331.
It is not a de Polignac number, because 133112000100343 - 21 = 133112000100341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133112000100341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21971283 + ... + 27367156.
It is an arithmetic number, because the mean of its divisors is an integer number (9155339603280).
Almost surely, 2133112000100343 is an apocalyptic number.
133112000100343 is a deficient number, since it is larger than the sum of its proper divisors (13373433552137).
133112000100343 is an equidigital number, since it uses as much as digits as its factorization.
133112000100343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49340499 (or 49340477 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 133112000100343 its reverse (343001000211331), we get a palindrome (476113000311674).
The spelling of 133112000100343 in words is "one hundred thirty-three trillion, one hundred twelve billion, one hundred thousand, three hundred forty-three".
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