Base | Representation |
---|---|
bin | 1100000110110100000101… |
… | …0111110001011110011111 |
3 | 1202010112112102221220011210 |
4 | 3001231001113301132133 |
5 | 3221042314300320221 |
6 | 44151025301115503 |
7 | 2542462645355211 |
oct | 301550127613637 |
9 | 52115472856153 |
10 | 13311200401311 |
11 | 42722806712aa |
12 | 15ab9720b8b93 |
13 | 7573190a9507 |
14 | 3403a08c25b1 |
15 | 1813c52bd276 |
hex | c1b415f179f |
13311200401311 has 8 divisors (see below), whose sum is σ = 17773585702704. Its totient is φ = 8861474350400.
The previous prime is 13311200401297. The next prime is 13311200401357. The reversal of 13311200401311 is 11310400211331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13311200401311 - 217 = 13311200270239 is a prime.
It is a super-2 number, since 2×133112004013112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13311200401381) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3164810166 + ... + 3164814371.
It is an arithmetic number, because the mean of its divisors is an integer number (2221698212838).
Almost surely, 213311200401311 is an apocalyptic number.
13311200401311 is a deficient number, since it is larger than the sum of its proper divisors (4462385301393).
13311200401311 is an equidigital number, since it uses as much as digits as its factorization.
13311200401311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6329625241.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 13311200401311 its reverse (11310400211331), we get a palindrome (24621600612642).
The spelling of 13311200401311 in words is "thirteen trillion, three hundred eleven billion, two hundred million, four hundred one thousand, three hundred eleven".
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