Base | Representation |
---|---|
bin | 1100000110110100001000… |
… | …0001000000011010100001 |
3 | 1202010112120012022001110110 |
4 | 3001231002001000122201 |
5 | 3221042330032213101 |
6 | 44151030324521533 |
7 | 2542463136264456 |
oct | 301550201003241 |
9 | 52115505261413 |
10 | 13311211210401 |
11 | 4272286784335 |
12 | 15ab9758502a9 |
13 | 75731b3c2420 |
14 | 3403a20d782d |
15 | 1813c6205cd6 |
hex | c1b420406a1 |
13311211210401 has 16 divisors (see below), whose sum is σ = 19114979607360. Its totient is φ = 8190895064640.
The previous prime is 13311211210391. The next prime is 13311211210469. The reversal of 13311211210401 is 10401211211331.
It is a happy number.
It is not a de Polignac number, because 13311211210401 - 27 = 13311211210273 is a prime.
It is a super-4 number, since 4×133112112104014 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is not an unprimeable number, because it can be changed into a prime (13311211212401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12384255 + ... + 13416116.
It is an arithmetic number, because the mean of its divisors is an integer number (1194686225460).
Almost surely, 213311211210401 is an apocalyptic number.
It is an amenable number.
13311211210401 is a deficient number, since it is larger than the sum of its proper divisors (5803768396959).
13311211210401 is a wasteful number, since it uses less digits than its factorization.
13311211210401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25813616.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 13311211210401 its reverse (10401211211331), we get a palindrome (23712422421732).
The spelling of 13311211210401 in words is "thirteen trillion, three hundred eleven billion, two hundred eleven million, two hundred ten thousand, four hundred one".
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