13311211224341 has 4 divisors (see below), whose sum is σ = 14011801288800. Its totient is φ = 12610621159884.

The previous prime is 13311211224319. The next prime is 13311211224373. The reversal of 13311211224341 is 14342211211331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13311211224341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311211224041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350295032201 + ... + 350295032238.

It is an arithmetic number, because the mean of its divisors is an integer number (3502950322200).

Almost surely, 2^{13311211224341} is an apocalyptic number.

It is an amenable number.

13311211224341 is a deficient number, since it is larger than the sum of its proper divisors (700590064459).

13311211224341 is an equidigital number, since it uses as much as digits as its factorization.

13311211224341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700590064458.

The product of its digits is 3456, while the sum is 29.

Adding to 13311211224341 its reverse (14342211211331), we get a palindrome (27653422435672).

The spelling of 13311211224341 in words is "thirteen trillion, three hundred eleven billion, two hundred eleven million, two hundred twenty-four thousand, three hundred forty-one".