Base | Representation |
---|---|
bin | 11000110010110100… |
… | …01111011100100111 |
3 | 1021100200101121010001 |
4 | 30121122033130213 |
5 | 204230132230203 |
6 | 10040505242131 |
7 | 650602300135 |
oct | 143132173447 |
9 | 37320347101 |
10 | 13311211303 |
11 | 5710917085 |
12 | 26b5a93347 |
13 | 13419c67c0 |
14 | 903c1a755 |
15 | 52d92791d |
hex | 31968f727 |
13311211303 has 16 divisors (see below), whose sum is σ = 14808371200. Its totient is φ = 11882233440.
The previous prime is 13311211261. The next prime is 13311211313. The reversal of 13311211303 is 30311211331.
It is a cyclic number.
It is not a de Polignac number, because 13311211303 - 29 = 13311210791 is a prime.
It is a super-2 number, since 2×133112113032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13311211313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 576658 + ... + 599296.
It is an arithmetic number, because the mean of its divisors is an integer number (925523200).
Almost surely, 213311211303 is an apocalyptic number.
13311211303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13311211303 is a deficient number, since it is larger than the sum of its proper divisors (1497159897).
13311211303 is a wasteful number, since it uses less digits than its factorization.
13311211303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24142.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13311211303 its reverse (30311211331), we get a palindrome (43622422634).
The spelling of 13311211303 in words is "thirteen billion, three hundred eleven million, two hundred eleven thousand, three hundred three".
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