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13311211320000 = 263254118340499
BaseRepresentation
bin1100000110110100001000…
…0001011011001011000000
31202010112120012111121210200
43001231002001123023000
53221042330044220000
644151030331125200
72542463140232136
oct301550201331300
952115505447720
1013311211320000
114272286849710
1215ab9758a3800
1375731b430289
143403a2125756
151813c6228500
hexc1b4205b2c0

13311211320000 has 840 divisors, whose sum is σ = 52639731144000. Its totient is φ = 3188002560000.

The previous prime is 13311211319953. The next prime is 13311211320041. The reversal of 13311211320000 is 2311211331.

13311211320000 is a `hidden beast` number, since 1 + 331 + 1 + 2 + 11 + 320 + 0 + 0 + 0 = 666.

It is a super-2 number, since 2×133112113200002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 328659751 + ... + 328700249.

It is an arithmetic number, because the mean of its divisors is an integer number (62666346600).

Almost surely, 213311211320000 is an apocalyptic number.

13311211320000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311211320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26319865572000).

13311211320000 is an abundant number, since it is smaller than the sum of its proper divisors (39328519824000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311211320000 is a wasteful number, since it uses less digits than its factorization.

13311211320000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40631 (or 40603 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13311211320000 its reverse (2311211331), we get a palindrome (13313522531331).

The spelling of 13311211320000 in words is "thirteen trillion, three hundred eleven billion, two hundred eleven million, three hundred twenty thousand".