Base | Representation |
---|---|
bin | 111101111111000011… |
… | …0110101100100100011 |
3 | 110201120211010121101200 |
4 | 1323332012311210203 |
5 | 4140103212132120 |
6 | 141052332532243 |
7 | 12421434143550 |
oct | 1737606654443 |
9 | 421524117350 |
10 | 133112224035 |
11 | 514a842010a |
12 | 2196b021083 |
13 | c7248bc80b |
14 | 662a965a27 |
15 | 36e11c3e90 |
hex | 1efe1b5923 |
133112224035 has 24 divisors (see below), whose sum is σ = 263688977760. Its totient is φ = 60851302272.
The previous prime is 133112224009. The next prime is 133112224061. The reversal of 133112224035 is 530422211331.
133112224035 is a `hidden beast` number, since 1 + 3 + 31 + 1 + 222 + 403 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (133112224009) and next prime (133112224061).
It is not a de Polignac number, because 133112224035 - 222 = 133108029731 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 211288930 + ... + 211289559.
It is an arithmetic number, because the mean of its divisors is an integer number (10987040740).
Almost surely, 2133112224035 is an apocalyptic number.
133112224035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
133112224035 is a deficient number, since it is larger than the sum of its proper divisors (130576753725).
133112224035 is a wasteful number, since it uses less digits than its factorization.
133112224035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 422578507 (or 422578504 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 133112224035 its reverse (530422211331), we get a palindrome (663534435366).
The spelling of 133112224035 in words is "one hundred thirty-three billion, one hundred twelve million, two hundred twenty-four thousand, thirty-five".
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