133113142033 has 4 divisors (see below), whose sum is σ = 133631092260. Its totient is φ = 132595191808.

The previous prime is 133113142031. The next prime is 133113142051. The reversal of 133113142033 is 330241311331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 59884452369 + 73228689664 = 244713^2 + 270608^2 .

It is a cyclic number.

It is not a de Polignac number, because 133113142033 - 2¹ = 133113142031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133113141989 and 133113142007.

It is not an unprimeable number, because it can be changed into a prime (133113142031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258974728 + ... + 258975241.

It is an arithmetic number, because the mean of its divisors is an integer number (33407773065).

Almost surely, 2^133113142033 is an apocalyptic number.

It is an amenable number.

133113142033 is a deficient number, since it is larger than the sum of its proper divisors (517950227).

133113142033 is an equidigital number, since it uses as much as digits as its factorization.

133113142033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 517950226.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 133113142033 its reverse (330241311331), we get a palindrome (463354453364).

The spelling of 133113142033 in words is "one hundred thirty-three billion, one hundred thirteen million, one hundred forty-two thousand, thirty-three".