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1331132330113 = 9024714749879
BaseRepresentation
bin10011010111101101101…
…010110111000010000001
311201020212220022200111121
4103113231222313002001
5133302124334030423
62455302545312241
7165112462055245
oct23275552670201
94636786280447
101331132330113
11473591552633
12195b95635681
13986a9c4c951
14485da14a425
152495c16e45d
hex135edab7081

1331132330113 has 4 divisors (see below), whose sum is σ = 1331147170240. Its totient is φ = 1331117489988.

The previous prime is 1331132330093. The next prime is 1331132330189. The reversal of 1331132330113 is 3110332311331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1331132330113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1331139330113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7284693 + ... + 7465186.

It is an arithmetic number, because the mean of its divisors is an integer number (332786792560).

Almost surely, 21331132330113 is an apocalyptic number.

It is an amenable number.

1331132330113 is a deficient number, since it is larger than the sum of its proper divisors (14840127).

1331132330113 is an equidigital number, since it uses as much as digits as its factorization.

1331132330113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14840126.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1331132330113 its reverse (3110332311331), we get a palindrome (4441464641444).

The spelling of 1331132330113 in words is "one trillion, three hundred thirty-one billion, one hundred thirty-two million, three hundred thirty thousand, one hundred thirteen".

Divisors: 1 90247 14749879 1331132330113