13311424320001 has 4 divisors (see below), whose sum is σ = 13311439000000. Its totient is φ = 13311409640004.

The previous prime is 13311424319993. The next prime is 13311424320067. The reversal of 13311424320001 is 10002342411331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13311424320001 - 2³ = 13311424319993 is a prime.

It is a super-2 number, since 2×13311424320001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13311424320071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5883501 + ... + 7825498.

It is an arithmetic number, because the mean of its divisors is an integer number (3327859750000).

Almost surely, 2^{13311424320001} is an apocalyptic number.

It is an amenable number.

13311424320001 is a deficient number, since it is larger than the sum of its proper divisors (14679999).

13311424320001 is an equidigital number, since it uses as much as digits as its factorization.

13311424320001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14679998.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13311424320001 its reverse (10002342411331), we get a palindrome (23313766731332).

The spelling of 13311424320001 in words is "thirteen trillion, three hundred eleven billion, four hundred twenty-four million, three hundred twenty thousand, one".