Base | Representation |
---|---|
bin | 1100000110110100111100… |
… | …1111100111011101010111 |
3 | 1202010120010122220110022222 |
4 | 3001231033033213131113 |
5 | 3221043303341103101 |
6 | 44151104333412555 |
7 | 2542501502553602 |
oct | 301551717473527 |
9 | 52116118813288 |
10 | 13311433144151 |
11 | 427238aa8845a |
12 | 15aba1803a15b |
13 | 75735538907c |
14 | 3403c3789339 |
15 | 1813da94401b |
hex | c1b4f3e7757 |
13311433144151 has 4 divisors (see below), whose sum is σ = 14012034888600. Its totient is φ = 12610831399704.
The previous prime is 13311433144133. The next prime is 13311433144159. The reversal of 13311433144151 is 15144133411331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13311433144151 - 238 = 13036555237207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13311433144159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350300872196 + ... + 350300872233.
It is an arithmetic number, because the mean of its divisors is an integer number (3503008722150).
Almost surely, 213311433144151 is an apocalyptic number.
13311433144151 is a deficient number, since it is larger than the sum of its proper divisors (700601744449).
13311433144151 is an equidigital number, since it uses as much as digits as its factorization.
13311433144151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 700601744448.
The product of its digits is 25920, while the sum is 35.
Adding to 13311433144151 its reverse (15144133411331), we get a palindrome (28455566555482).
The spelling of 13311433144151 in words is "thirteen trillion, three hundred eleven billion, four hundred thirty-three million, one hundred forty-four thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •