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1331144403 = 3443714801
BaseRepresentation
bin100111101010111…
…1010011011010011
310102202210010211120
41033111322123103
510211233110103
6340031013323
744662353321
oct11725723323
93382703746
101331144403
1162343a546
1231196a243
13182a20b14
14c8b0ad11
157bce3253
hex4f57a6d3

1331144403 has 4 divisors (see below), whose sum is σ = 1774859208. Its totient is φ = 887429600.

The previous prime is 1331144401. The next prime is 1331144411. The reversal of 1331144403 is 3044411331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1331144403 - 21 = 1331144401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1331144401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221857398 + ... + 221857403.

It is an arithmetic number, because the mean of its divisors is an integer number (443714802).

Almost surely, 21331144403 is an apocalyptic number.

1331144403 is a deficient number, since it is larger than the sum of its proper divisors (443714805).

1331144403 is an equidigital number, since it uses as much as digits as its factorization.

1331144403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 443714804.

The product of its (nonzero) digits is 1728, while the sum is 24.

The square root of 1331144403 is about 36484.8516921749. The cubic root of 1331144403 is about 1100.0397790022.

Adding to 1331144403 its reverse (3044411331), we get a palindrome (4375555734).

The spelling of 1331144403 in words is "one billion, three hundred thirty-one million, one hundred forty-four thousand, four hundred three".

Divisors: 1 3 443714801 1331144403