Base | Representation |
---|---|
bin | 11110010001000101011010… |
… | …000110110010011111110111 |
3 | 122110022201012102002100101211 |
4 | 132101011122012302133313 |
5 | 114421430401340242241 |
6 | 1151040215154102251 |
7 | 40016162345336203 |
oct | 3621053206623767 |
9 | 573281172070354 |
10 | 133115433134071 |
11 | 39461a35768063 |
12 | 12b1a7b527a987 |
13 | 59379680b37cb |
14 | 24c2b6da87b03 |
15 | 105c987d97781 |
hex | 79115a1b27f7 |
133115433134071 has 8 divisors (see below), whose sum is σ = 140128268009600. Its totient is φ = 126103274203320.
The previous prime is 133115433134069. The next prime is 133115433134077. The reversal of 133115433134071 is 170431334511331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133115433134071 - 21 = 133115433134069 is a prime.
It is a super-2 number, since 2×1331154331340712 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133115433134077) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 168581931 + ... + 169369708.
It is an arithmetic number, because the mean of its divisors is an integer number (17516033501200).
Almost surely, 2133115433134071 is an apocalyptic number.
133115433134071 is a deficient number, since it is larger than the sum of its proper divisors (7012834875529).
133115433134071 is a wasteful number, since it uses less digits than its factorization.
133115433134071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 337972389.
The product of its (nonzero) digits is 136080, while the sum is 40.
The spelling of 133115433134071 in words is "one hundred thirty-three trillion, one hundred fifteen billion, four hundred thirty-three million, one hundred thirty-four thousand, seventy-one".
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