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13312004202403 = 17650775419129
BaseRepresentation
bin1100000110110111000101…
…0010000001111110100011
31202010121121110110012222121
43001231301102001332203
53221100441033434103
644151241133245111
72542521605512504
oct301556122017643
952117543405877
1013312004202403
114272653368a25
1215abb57333797
1375741679056a
1434043955abab
15181420b466bd
hexc1b71481fa3

13312004202403 has 4 divisors (see below), whose sum is σ = 13312079798040. Its totient is φ = 13311928606768.

The previous prime is 13312004202373. The next prime is 13312004202437. The reversal of 13312004202403 is 30420240021331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13312004202403 - 213 = 13312004194211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13312004202703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37533058 + ... + 37886071.

It is an arithmetic number, because the mean of its divisors is an integer number (3328019949510).

Almost surely, 213312004202403 is an apocalyptic number.

13312004202403 is a deficient number, since it is larger than the sum of its proper divisors (75595637).

13312004202403 is an equidigital number, since it uses as much as digits as its factorization.

13312004202403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75595636.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13312004202403 its reverse (30420240021331), we get a palindrome (43732244223734).

The spelling of 13312004202403 in words is "thirteen trillion, three hundred twelve billion, four million, two hundred two thousand, four hundred three".

Divisors: 1 176507 75419129 13312004202403