Base | Representation |
---|---|
bin | 10011010111110001110… |
… | …001010100101111000001 |
3 | 11201021001200210021000101 |
4 | 103113301301110233001 |
5 | 133302244442233010 |
6 | 2455313444122401 |
7 | 165114255636235 |
oct | 23276161245701 |
9 | 4637050707011 |
10 | 1331201133505 |
11 | 473617376641 |
12 | 195bb4696401 |
13 | 986bb28c909 |
14 | 4860533a5c5 |
15 | 2496321073a |
hex | 135f1c54bc1 |
1331201133505 has 4 divisors (see below), whose sum is σ = 1597441360212. Its totient is φ = 1064960906800.
The previous prime is 1331201133497. The next prime is 1331201133547. The reversal of 1331201133505 is 5053311021331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 990510619536 + 340690513969 = 995244^2 + 583687^2 .
It is not a de Polignac number, because 1331201133505 - 23 = 1331201133497 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133120113346 + ... + 133120113355.
It is an arithmetic number, because the mean of its divisors is an integer number (399360340053).
Almost surely, 21331201133505 is an apocalyptic number.
It is an amenable number.
1331201133505 is a deficient number, since it is larger than the sum of its proper divisors (266240226707).
1331201133505 is an equidigital number, since it uses as much as digits as its factorization.
1331201133505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 266240226706.
The product of its (nonzero) digits is 4050, while the sum is 28.
Adding to 1331201133505 its reverse (5053311021331), we get a palindrome (6384512154836).
The spelling of 1331201133505 in words is "one trillion, three hundred thirty-one billion, two hundred one million, one hundred thirty-three thousand, five hundred five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.029 sec. • engine limits •