Search a number
-
+
133120201403 = 751473694807
BaseRepresentation
bin111101111111010010…
…1010001001010111011
3110201121101010220021202
41323332211101022323
54140112232421103
6141053215524415
712421562020310
oct1737645211273
9421541126252
10133120201403
1151501979682
122197182970b
13c726453857
14662ba40d07
1536e1c4c988
hex1efe9512bb

133120201403 has 8 divisors (see below), whose sum is σ = 152166972672. Its totient is φ = 114080830056.

The previous prime is 133120201387. The next prime is 133120201441. The reversal of 133120201403 is 304102021331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133120201403 - 24 = 133120201387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133120201483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1811375 + ... + 1883432.

It is an arithmetic number, because the mean of its divisors is an integer number (19020871584).

Almost surely, 2133120201403 is an apocalyptic number.

133120201403 is a deficient number, since it is larger than the sum of its proper divisors (19046771269).

133120201403 is an equidigital number, since it uses as much as digits as its factorization.

133120201403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3699961.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 133120201403 its reverse (304102021331), we get a palindrome (437222222734).

The spelling of 133120201403 in words is "one hundred thirty-three billion, one hundred twenty million, two hundred one thousand, four hundred three".

Divisors: 1 7 5147 36029 3694807 25863649 19017171629 133120201403