Base | Representation |
---|---|
bin | 1100000110110111001000… |
… | …1111000100011100100111 |
3 | 1202010121122120120011002112 |
4 | 3001231302033010130213 |
5 | 3221101004133001203 |
6 | 44151242504231235 |
7 | 2542522161514403 |
oct | 301556217043447 |
9 | 52117576504075 |
10 | 13312020203303 |
11 | 42726613a7708 |
12 | 15abb6076b51b |
13 | 757419ba3653 |
14 | 34043b724103 |
15 | 1814222576d8 |
hex | c1b723c4727 |
13312020203303 has 16 divisors (see below), whose sum is σ = 14505038748000. Its totient is φ = 12165909820416.
The previous prime is 13312020203281. The next prime is 13312020203309. The reversal of 13312020203303 is 30330202021331.
13312020203303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13312020203303 - 210 = 13312020202279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13312020203309) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20892326 + ... + 21520067.
It is an arithmetic number, because the mean of its divisors is an integer number (906564921750).
Almost surely, 213312020203303 is an apocalyptic number.
13312020203303 is a deficient number, since it is larger than the sum of its proper divisors (1193018544697).
13312020203303 is a wasteful number, since it uses less digits than its factorization.
13312020203303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42412946.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 13312020203303 its reverse (30330202021331), we get a palindrome (43642222224634).
The spelling of 13312020203303 in words is "thirteen trillion, three hundred twelve billion, twenty million, two hundred three thousand, three hundred three".
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