Base | Representation |
---|---|
bin | 111101111111010100… |
… | …0011100011101110101 |
3 | 110201121102201012112102 |
4 | 1323332220130131311 |
5 | 4140112441042401 |
6 | 141053245431445 |
7 | 12421602056066 |
oct | 1737650343565 |
9 | 421542635472 |
10 | 133121034101 |
11 | 51502398260 |
12 | 21971b6b585 |
13 | c726685883 |
14 | 662bbba56d |
15 | 36e1d6456b |
hex | 1efea1c775 |
133121034101 has 4 divisors (see below), whose sum is σ = 145222946304. Its totient is φ = 121019121900.
The previous prime is 133121034089. The next prime is 133121034103. The reversal of 133121034101 is 101430121331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133121034101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133121034103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6050956085 + ... + 6050956106.
It is an arithmetic number, because the mean of its divisors is an integer number (36305736576).
Almost surely, 2133121034101 is an apocalyptic number.
133121034101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
133121034101 is a deficient number, since it is larger than the sum of its proper divisors (12101912203).
133121034101 is a wasteful number, since it uses less digits than its factorization.
133121034101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12101912202.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 133121034101 its reverse (101430121331), we get a palindrome (234551155432).
The spelling of 133121034101 in words is "one hundred thirty-three billion, one hundred twenty-one million, thirty-four thousand, one hundred one".
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