133121233100434 has 4 divisors (see below), whose sum is σ = 199681849650654. Its totient is φ = 66560616550216.

The previous prime is 133121233100423. The next prime is 133121233100447. The reversal of 133121233100434 is 434001332121331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 67784808321409 + 65336424779025 = 8233153^2 + 8083095^2 .

It is a junction number, because it is equal to n+sod(n) for n = 133121233100396 and 133121233100405.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33280308275107 + ... + 33280308275110.

Almost surely, 2^{133121233100434} is an apocalyptic number.

133121233100434 is a deficient number, since it is larger than the sum of its proper divisors (66560616550220).

133121233100434 is an equidigital number, since it uses as much as digits as its factorization.

133121233100434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66560616550219.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 133121233100434 its reverse (434001332121331), we get a palindrome (567122565221765).

The spelling of 133121233100434 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, two hundred thirty-three million, one hundred thousand, four hundred thirty-four".