Base | Representation |
---|---|
bin | 11000110010111011… |
… | …10000001111000001 |
3 | 1021100202010101010011 |
4 | 30121131300033001 |
5 | 204230401211113 |
6 | 10040541104521 |
7 | 650613153364 |
oct | 143135601701 |
9 | 37322111104 |
10 | 13312132033 |
11 | 5711395912 |
12 | 26b6258141 |
13 | 1341c59905 |
14 | 903dba0db |
15 | 52da5a63d |
hex | 3197703c1 |
13312132033 has 4 divisors (see below), whose sum is σ = 13313170368. Its totient is φ = 13311093700.
The previous prime is 13312132019. The next prime is 13312132037. The reversal of 13312132033 is 33023121331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33023121331 = 647 ⋅51040373.
It is a cyclic number.
It is not a de Polignac number, because 13312132033 - 213 = 13312123841 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13312131995 and 13312132013.
It is not an unprimeable number, because it can be changed into a prime (13312132037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 499693 + ... + 525658.
It is an arithmetic number, because the mean of its divisors is an integer number (3328292592).
Almost surely, 213312132033 is an apocalyptic number.
It is an amenable number.
13312132033 is a deficient number, since it is larger than the sum of its proper divisors (1038335).
13312132033 is a wasteful number, since it uses less digits than its factorization.
13312132033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1038334.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 13312132033 its reverse (33023121331), we get a palindrome (46335253364).
The spelling of 13312132033 in words is "thirteen billion, three hundred twelve million, one hundred thirty-two thousand, thirty-three".
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