13312143420131 has 4 divisors (see below), whose sum is σ = 13338608914512. Its totient is φ = 13285677925752.

The previous prime is 13312143420113. The next prime is 13312143420193. The reversal of 13312143420131 is 13102434121331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13312143420131 - 2³⁰ = 13311069678307 is a prime.

It is a super-2 number, since 2×13312143420131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13312143420094 and 13312143420103.

It is not an unprimeable number, because it can be changed into a prime (13312143440131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13232746436 + ... + 13232747441.

It is an arithmetic number, because the mean of its divisors is an integer number (3334652228628).

Almost surely, 2^{13312143420131} is an apocalyptic number.

13312143420131 is a deficient number, since it is larger than the sum of its proper divisors (26465494381).

13312143420131 is an equidigital number, since it uses as much as digits as its factorization.

13312143420131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26465494380.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13312143420131 its reverse (13102434121331), we get a palindrome (26414577541462).

The spelling of 13312143420131 in words is "thirteen trillion, three hundred twelve billion, one hundred forty-three million, four hundred twenty thousand, one hundred thirty-one".