Base | Representation |
---|---|
bin | 1100000110110111100110… |
… | …0101000110101011100010 |
3 | 1202010121222011102012210201 |
4 | 3001231321211012223202 |
5 | 3221101232203421010 |
6 | 44151303025215414 |
7 | 2542525216034212 |
oct | 301557145065342 |
9 | 52117864365721 |
10 | 13312143420130 |
11 | 4272714a062a5 |
12 | 15abb95a9156a |
13 | 757439585809 |
14 | 34044dc3a242 |
15 | 18142ce9623a |
hex | c1b79946ae2 |
13312143420130 has 16 divisors (see below), whose sum is σ = 24231092519160. Its totient is φ = 5265027509632.
The previous prime is 13312143420113. The next prime is 13312143420193. The reversal of 13312143420130 is 3102434121331.
13312143420130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 3761997730569 + 9550145689561 = 1939587^2 + 3090331^2 .
It is a super-2 number, since 2×133121434201302 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7478731369 + ... + 7478733148.
Almost surely, 213312143420130 is an apocalyptic number.
13312143420130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13312143420130 is a deficient number, since it is larger than the sum of its proper divisors (10918949099030).
13312143420130 is a wasteful number, since it uses less digits than its factorization.
13312143420130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14957464613.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13312143420130 its reverse (3102434121331), we get a palindrome (16414577541461).
The spelling of 13312143420130 in words is "thirteen trillion, three hundred twelve billion, one hundred forty-three million, four hundred twenty thousand, one hundred thirty".
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