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13312151553 = 34437383851
BaseRepresentation
bin11000110010111011…
…10101000000000001
31021100202011100220010
430121131311000001
5204230402322203
610040541335133
7650613264321
oct143135650001
937322140803
1013312151553
1157113a9548
1226b62674a9
131341c6576c
14903dc3281
1552da61303
hex319775001

13312151553 has 4 divisors (see below), whose sum is σ = 17749535408. Its totient is φ = 8874767700.

The previous prime is 13312151521. The next prime is 13312151641. The reversal of 13312151553 is 35515121331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13312151553 - 25 = 13312151521 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13312151553.

It is not an unprimeable number, because it can be changed into a prime (13312151353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218691923 + ... + 2218691928.

It is an arithmetic number, because the mean of its divisors is an integer number (4437383852).

Almost surely, 213312151553 is an apocalyptic number.

It is an amenable number.

13312151553 is a deficient number, since it is larger than the sum of its proper divisors (4437383855).

13312151553 is an equidigital number, since it uses as much as digits as its factorization.

13312151553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4437383854.

The product of its digits is 6750, while the sum is 30.

Adding to 13312151553 its reverse (35515121331), we get a palindrome (48827272884).

The spelling of 13312151553 in words is "thirteen billion, three hundred twelve million, one hundred fifty-one thousand, five hundred fifty-three".

Divisors: 1 3 4437383851 13312151553