1331244303041 has 4 divisors (see below), whose sum is σ = 1332091691184. Its totient is φ = 1330396914900.

The previous prime is 1331244303023. The next prime is 1331244303061. The reversal of 1331244303041 is 1403034421331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331244303041 - 2³⁸ = 1056366396097 is a prime.

It is a super-2 number, since 2×1331244303041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331244302995 and 1331244303013.

It is not an unprimeable number, because it can be changed into a prime (1331244303061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 423691715 + ... + 423694856.

It is an arithmetic number, because the mean of its divisors is an integer number (333022922796).

Almost surely, 2^{1331244303041} is an apocalyptic number.

It is an amenable number.

1331244303041 is a deficient number, since it is larger than the sum of its proper divisors (847388143).

1331244303041 is an equidigital number, since it uses as much as digits as its factorization.

1331244303041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 847388142.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 1331244303041 its reverse (1403034421331), we get a palindrome (2734278724372).

The spelling of 1331244303041 in words is "one trillion, three hundred thirty-one billion, two hundred forty-four million, three hundred three thousand, forty-one".