Base | Representation |
---|---|
bin | 111101111111011100… |
… | …1000100110110110000 |
3 | 110201121201220200222020 |
4 | 1323332321010312300 |
5 | 4140120100100330 |
6 | 141053523111440 |
7 | 12421654114515 |
oct | 1737671046660 |
9 | 421551820866 |
10 | 133125393840 |
11 | 515048a584a |
12 | 21973512580 |
13 | c7275510ba |
14 | 662c5d330c |
15 | 36e2426210 |
hex | 1efee44db0 |
133125393840 has 320 divisors, whose sum is σ = 441491492736. Its totient is φ = 33067892736.
The previous prime is 133125393773. The next prime is 133125393893. The reversal of 133125393840 is 48393521331.
It is a junction number, because it is equal to n+sod(n) for n = 133125393792 and 133125393801.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 230719632 + ... + 230720208.
Almost surely, 2133125393840 is an apocalyptic number.
133125393840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133125393840, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (220745746368).
133125393840 is an abundant number, since it is smaller than the sum of its proper divisors (308366098896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133125393840 is a wasteful number, since it uses less digits than its factorization.
133125393840 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1096 (or 1090 counting only the distinct ones).
The product of its (nonzero) digits is 233280, while the sum is 42.
The spelling of 133125393840 in words is "one hundred thirty-three billion, one hundred twenty-five million, three hundred ninety-three thousand, eight hundred forty".
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