13313011440413 has 4 divisors (see below), whose sum is σ = 13313165803548. Its totient is φ = 13312857077280.

The previous prime is 13313011440409. The next prime is 13313011440427. The reversal of 13313011440413 is 31404411031331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2040789387844 + 11272222052569 = 1428562^2 + 3357413^2 .

It is a cyclic number.

It is not a de Polignac number, because 13313011440413 - 2² = 13313011440409 is a prime.

It is a super-2 number, since 2×13313011440413² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13313011440013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77052128 + ... + 77224713.

It is an arithmetic number, because the mean of its divisors is an integer number (3328291450887).

Almost surely, 2^{13313011440413} is an apocalyptic number.

It is an amenable number.

13313011440413 is a deficient number, since it is larger than the sum of its proper divisors (154363135).

13313011440413 is an equidigital number, since it uses as much as digits as its factorization.

13313011440413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154363134.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13313011440413 its reverse (31404411031331), we get a palindrome (44717422471744).

The spelling of 13313011440413 in words is "thirteen trillion, three hundred thirteen billion, eleven million, four hundred forty thousand, four hundred thirteen".