Base | Representation |
---|---|
bin | 111101111111100110… |
… | …0011000101001010111 |
3 | 110201122002102212110021 |
4 | 1323333030120221113 |
5 | 4140122344040024 |
6 | 141054223410011 |
7 | 12422045126116 |
oct | 1737714305127 |
9 | 421562385407 |
10 | 133130455639 |
11 | 51507742855 |
12 | 21975153907 |
13 | c72860404c |
14 | 662d14dc7d |
15 | 36e2ac5de4 |
hex | 1eff318a57 |
133130455639 has 4 divisors (see below), whose sum is σ = 134815651360. Its totient is φ = 131445259920.
The previous prime is 133130455621. The next prime is 133130455669. The reversal of 133130455639 is 936554031331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133130455639 - 215 = 133130422871 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133130455595 and 133130455604.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133130455669) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 842597742 + ... + 842597899.
It is an arithmetic number, because the mean of its divisors is an integer number (33703912840).
Almost surely, 2133130455639 is an apocalyptic number.
133130455639 is a deficient number, since it is larger than the sum of its proper divisors (1685195721).
133130455639 is an equidigital number, since it uses as much as digits as its factorization.
133130455639 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1685195720.
The product of its (nonzero) digits is 437400, while the sum is 43.
The spelling of 133130455639 in words is "one hundred thirty-three billion, one hundred thirty million, four hundred fifty-five thousand, six hundred thirty-nine".
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