133131030023113 has 4 divisors (see below), whose sum is σ = 135006114953088. Its totient is φ = 131255945093140.

The previous prime is 133131030023099. The next prime is 133131030023137. The reversal of 133131030023113 is 311320030131331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133131030023113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133131030023143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 937542464881 + ... + 937542465022.

It is an arithmetic number, because the mean of its divisors is an integer number (33751528738272).

Almost surely, 2^{133131030023113} is an apocalyptic number.

It is an amenable number.

133131030023113 is a deficient number, since it is larger than the sum of its proper divisors (1875084929975).

133131030023113 is an equidigital number, since it uses as much as digits as its factorization.

133131030023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1875084929974.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 133131030023113 its reverse (311320030131331), we get a palindrome (444451060154444).

The spelling of 133131030023113 in words is "one hundred thirty-three trillion, one hundred thirty-one billion, thirty million, twenty-three thousand, one hundred thirteen".