Search a number
-
+
133131121301 = 971137107231
BaseRepresentation
bin111101111111100111…
…0111011001010010101
3110201122010200200120102
41323333032323022111
54140123031340201
6141054245543445
712422053600613
oct1737716731225
9421563620512
10133131121301
1151508057992
1221975414b85
13c7287a8029
14662d2846b3
1536e2ba826b
hex1eff3bb295

133131121301 has 4 divisors (see below), whose sum is σ = 133268229504. Its totient is φ = 132994013100.

The previous prime is 133131121273. The next prime is 133131121307. The reversal of 133131121301 is 103121131331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133131121301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133131121307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68552645 + ... + 68554586.

It is an arithmetic number, because the mean of its divisors is an integer number (33317057376).

Almost surely, 2133131121301 is an apocalyptic number.

It is an amenable number.

133131121301 is a deficient number, since it is larger than the sum of its proper divisors (137108203).

133131121301 is an equidigital number, since it uses as much as digits as its factorization.

133131121301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137108202.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 133131121301 its reverse (103121131331), we get a palindrome (236252252632).

The spelling of 133131121301 in words is "one hundred thirty-three billion, one hundred thirty-one million, one hundred twenty-one thousand, three hundred one".

Divisors: 1 971 137107231 133131121301