133132204424041 has 4 divisors (see below), whose sum is σ = 133132632303184. Its totient is φ = 133131776544900.

The previous prime is 133132204424033. The next prime is 133132204424057. The reversal of 133132204424041 is 140424402231331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133132204424041 - 2³ = 133132204424033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133132204423988 and 133132204424006.

It is not an unprimeable number, because it can be changed into a prime (133132204424941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213472515 + ... + 214095256.

It is an arithmetic number, because the mean of its divisors is an integer number (33283158075796).

Almost surely, 2^{133132204424041} is an apocalyptic number.

It is an amenable number.

133132204424041 is a deficient number, since it is larger than the sum of its proper divisors (427879143).

133132204424041 is an equidigital number, since it uses as much as digits as its factorization.

133132204424041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 427879142.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 133132204424041 its reverse (140424402231331), we get a palindrome (273556606655372).

The spelling of 133132204424041 in words is "one hundred thirty-three trillion, one hundred thirty-two billion, two hundred four million, four hundred twenty-four thousand, forty-one".