Base | Representation |
---|---|
bin | 11000110011000100… |
… | …01101101011100101 |
3 | 1021100211022202221102 |
4 | 30121202031223211 |
5 | 204231201114341 |
6 | 10041022125445 |
7 | 650626123163 |
oct | 143142155345 |
9 | 37324282842 |
10 | 13313301221 |
11 | 5712014290 |
12 | 26b6720885 |
13 | 1342278b3c |
14 | 904202233 |
15 | 52dbdbc9b |
hex | 31988dae5 |
13313301221 has 4 divisors (see below), whose sum is σ = 14523601344. Its totient is φ = 12103001100.
The previous prime is 13313301193. The next prime is 13313301223. The reversal of 13313301221 is 12210331331.
13313301221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12210331331 = 11 ⋅1110030121.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13313301221 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13313301193 and 13313301202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13313301223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605150045 + ... + 605150066.
It is an arithmetic number, because the mean of its divisors is an integer number (3630900336).
Almost surely, 213313301221 is an apocalyptic number.
13313301221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13313301221 is a deficient number, since it is larger than the sum of its proper divisors (1210300123).
13313301221 is a wasteful number, since it uses less digits than its factorization.
13313301221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1210300122.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 13313301221 its reverse (12210331331), we get a palindrome (25523632552).
The spelling of 13313301221 in words is "thirteen billion, three hundred thirteen million, three hundred one thousand, two hundred twenty-one".
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