Base | Representation |
---|---|
bin | 1100000110111100000001… |
… | …1011010010111000100011 |
3 | 1202010202000222222220101221 |
4 | 3001233000123102320203 |
5 | 3221111200444443021 |
6 | 44152021005235511 |
7 | 2542566531046105 |
oct | 301570033227043 |
9 | 52122028886357 |
10 | 13313332031011 |
11 | 4273174943241 |
12 | 15b0267b62b97 |
13 | 7575988c006c |
14 | 340523a43575 |
15 | 18149c4d2241 |
hex | c1bc06d2e23 |
13313332031011 has 4 divisors (see below), whose sum is σ = 13742794354624. Its totient is φ = 12883869707400.
The previous prime is 13313332030997. The next prime is 13313332031071. The reversal of 13313332031011 is 11013023331331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13313332031011 - 217 = 13313331899939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13313332031071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214731161760 + ... + 214731161821.
It is an arithmetic number, because the mean of its divisors is an integer number (3435698588656).
Almost surely, 213313332031011 is an apocalyptic number.
13313332031011 is a deficient number, since it is larger than the sum of its proper divisors (429462323613).
13313332031011 is an equidigital number, since it uses as much as digits as its factorization.
13313332031011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429462323612.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13313332031011 its reverse (11013023331331), we get a palindrome (24326355362342).
The spelling of 13313332031011 in words is "thirteen trillion, three hundred thirteen billion, three hundred thirty-two million, thirty-one thousand, eleven".
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