133143000520333 has 4 divisors (see below), whose sum is σ = 137734138469340. Its totient is φ = 128551862571328.

The previous prime is 133143000520331. The next prime is 133143000520403. The reversal of 133143000520333 is 333025000341331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 83950984775529 + 49192015744804 = 9162477^2 + 7013702^2 .

It is a cyclic number.

It is not a de Polignac number, because 133143000520333 - 2¹ = 133143000520331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133143000520295 and 133143000520304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133143000520331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2295568974460 + ... + 2295568974517.

It is an arithmetic number, because the mean of its divisors is an integer number (34433534617335).

Almost surely, 2^{133143000520333} is an apocalyptic number.

It is an amenable number.

133143000520333 is a deficient number, since it is larger than the sum of its proper divisors (4591137949007).

133143000520333 is an equidigital number, since it uses as much as digits as its factorization.

133143000520333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4591137949006.

The product of its (nonzero) digits is 29160, while the sum is 31.

Adding to 133143000520333 its reverse (333025000341331), we get a palindrome (466168000861664).

The spelling of 133143000520333 in words is "one hundred thirty-three trillion, one hundred forty-three billion, five hundred twenty thousand, three hundred thirty-three".