13314311114031 has 8 divisors (see below), whose sum is σ = 19724905354160. Its totient is φ = 8876207409336.

The previous prime is 13314311113969. The next prime is 13314311114033. The reversal of 13314311114031 is 13041111341331.

13314311114031 is a `hidden beast` number, since 1 + 3 + 3 + 143 + 1 + 111 + 403 + 1 = 666.

It is not a de Polignac number, because 13314311114031 - 2⁷ = 13314311113903 is a prime.

It is a super-2 number, since 2×13314311114031² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 493122633853 = 13314311114031 / (1 + 3 + 3 + 1 + 4 + 3 + 1 + 1 + 1 + 1 + 4 + 0 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13314311113986 and 13314311114004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13314311114033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 246561316900 + ... + 246561316953.

It is an arithmetic number, because the mean of its divisors is an integer number (2465613169270).

Almost surely, 2^{13314311114031} is an apocalyptic number.

13314311114031 is a deficient number, since it is larger than the sum of its proper divisors (6410594240129).

13314311114031 is an equidigital number, since it uses as much as digits as its factorization.

13314311114031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 493122633862 (or 493122633856 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 27.

Adding to 13314311114031 its reverse (13041111341331), we get a palindrome (26355422455362).

The spelling of 13314311114031 in words is "thirteen trillion, three hundred fourteen billion, three hundred eleven million, one hundred fourteen thousand, thirty-one".