1331491433103 has 12 divisors (see below), whose sum is σ = 2071208896120. Its totient is φ = 819379343376.

The previous prime is 1331491433099. The next prime is 1331491433117. The reversal of 1331491433103 is 3013341941331.

1331491433103 is a `hidden beast` number, since 1 + 3 + 31 + 4 + 91 + 433 + 103 = 666.

It is not a de Polignac number, because 1331491433103 - 2² = 1331491433099 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331491433003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5690134213 + ... + 5690134446.

Almost surely, 2^{1331491433103} is an apocalyptic number.

1331491433103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1331491433103 is a deficient number, since it is larger than the sum of its proper divisors (739717463017).

1331491433103 is a wasteful number, since it uses less digits than its factorization.

1331491433103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11380268678 (or 11380268675 counting only the distinct ones).

The product of its (nonzero) digits is 34992, while the sum is 36.

The spelling of 1331491433103 in words is "one trillion, three hundred thirty-one billion, four hundred ninety-one million, four hundred thirty-three thousand, one hundred three".