13315320033 has 4 divisors (see below), whose sum is σ = 17753760048. Its totient is φ = 8876880020.

The previous prime is 13315320017. The next prime is 13315320059. The reversal of 13315320033 is 33002351331.

13315320033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33002351331 = 3 ⋅11000783777.

It is a cyclic number.

It is not a de Polignac number, because 13315320033 - 2⁴ = 13315320017 is a prime.

It is a super-2 number, since 2×13315320033² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13315319985 and 13315320012.

It is not an unprimeable number, because it can be changed into a prime (13315320013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2219220003 + ... + 2219220008.

It is an arithmetic number, because the mean of its divisors is an integer number (4438440012).

Almost surely, 2^13315320033 is an apocalyptic number.

It is an amenable number.

13315320033 is a deficient number, since it is larger than the sum of its proper divisors (4438440015).

13315320033 is an equidigital number, since it uses as much as digits as its factorization.

13315320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4438440014.

The product of its (nonzero) digits is 2430, while the sum is 24.

Adding to 13315320033 its reverse (33002351331), we get a palindrome (46317671364).

The spelling of 13315320033 in words is "thirteen billion, three hundred fifteen million, three hundred twenty thousand, thirty-three".