Base | Representation |
---|---|
bin | 1100000111010100111100… |
… | …0111110001000101000111 |
3 | 1202011101022011111210122212 |
4 | 3001311033013301011013 |
5 | 3221213400340132444 |
6 | 44155044433414035 |
7 | 2543224352401460 |
oct | 301651707610507 |
9 | 52141264453585 |
10 | 13320021020999 |
11 | 4275a97683440 |
12 | 15b161410a31b |
13 | 7580c36419c4 |
14 | 34099a161d67 |
15 | 18173e86519e |
hex | c1d4f1f1147 |
13320021020999 has 16 divisors (see below), whose sum is σ = 16607857410816. Its totient is φ = 10378563436800.
The previous prime is 13320021020989. The next prime is 13320021021007. The reversal of 13320021020999 is 99902012002331.
13320021020999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13320021020999 - 220 = 13320019972423 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13320021020989) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4418762 + ... + 6794519.
It is an arithmetic number, because the mean of its divisors is an integer number (1037991088176).
Almost surely, 213320021020999 is an apocalyptic number.
13320021020999 is a deficient number, since it is larger than the sum of its proper divisors (3287836389817).
13320021020999 is a wasteful number, since it uses less digits than its factorization.
13320021020999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11228726.
The product of its (nonzero) digits is 52488, while the sum is 41.
The spelling of 13320021020999 in words is "thirteen trillion, three hundred twenty billion, twenty-one million, twenty thousand, nine hundred ninety-nine".
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