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133200213301 = 831604821847
BaseRepresentation
bin111110000001101011…
…0011111010100110101
3110201210221200220222101
41330003112133110311
54140243223311201
6141105154502101
712423553063201
oct1740326372465
9421727626871
10133200213301
1151543058811
1221994594931
13c739bb947c
14663850bb01
1536e8ca4d01
hex1f0359f535

133200213301 has 4 divisors (see below), whose sum is σ = 134805035232. Its totient is φ = 131595391372.

The previous prime is 133200213257. The next prime is 133200213313. The reversal of 133200213301 is 103312002331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133200213301 - 211 = 133200211253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133200213401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 802410841 + ... + 802411006.

It is an arithmetic number, because the mean of its divisors is an integer number (33701258808).

Almost surely, 2133200213301 is an apocalyptic number.

It is an amenable number.

133200213301 is a deficient number, since it is larger than the sum of its proper divisors (1604821931).

133200213301 is an equidigital number, since it uses as much as digits as its factorization.

133200213301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1604821930.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 133200213301 its reverse (103312002331), we get a palindrome (236512215632).

The spelling of 133200213301 in words is "one hundred thirty-three billion, two hundred million, two hundred thirteen thousand, three hundred one".

Divisors: 1 83 1604821847 133200213301