13320110200013 has 4 divisors (see below), whose sum is σ = 13320202584480. Its totient is φ = 13320017815548.

The previous prime is 13320110199973. The next prime is 13320110200073. The reversal of 13320110200013 is 31000201102331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13320110200013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13320110199964 and 13320110200000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13320110200073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45975623 + ... + 46264436.

It is an arithmetic number, because the mean of its divisors is an integer number (3330050646120).

Almost surely, 2^{13320110200013} is an apocalyptic number.

It is an amenable number.

13320110200013 is a deficient number, since it is larger than the sum of its proper divisors (92384467).

13320110200013 is an equidigital number, since it uses as much as digits as its factorization.

13320110200013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92384466.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13320110200013 its reverse (31000201102331), we get a palindrome (44320311302344).

The spelling of 13320110200013 in words is "thirteen trillion, three hundred twenty billion, one hundred ten million, two hundred thousand, thirteen".