1332011045434 has 4 divisors (see below), whose sum is σ = 1998016568154. Its totient is φ = 666005522716.

The previous prime is 1332011045389. The next prime is 1332011045459. The reversal of 1332011045434 is 4345401102331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 969663631225 + 362347414209 = 984715^2 + 601953^2 .

It is a super-2 number, since 2×1332011045434² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1332011045396 and 1332011045405.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333002761357 + ... + 333002761360.

Almost surely, 2^{1332011045434} is an apocalyptic number.

1332011045434 is a deficient number, since it is larger than the sum of its proper divisors (666005522720).

1332011045434 is an equidigital number, since it uses as much as digits as its factorization.

1332011045434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 666005522719.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1332011045434 its reverse (4345401102331), we get a palindrome (5677412147765).

The spelling of 1332011045434 in words is "one trillion, three hundred thirty-two billion, eleven million, forty-five thousand, four hundred thirty-four".