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1332012010103 = 2266958759187
BaseRepresentation
bin10011011000100010000…
…110100100101001110111
311201100011012121001120222
4103120202012210221313
5133310430033310403
62455530132044555
7165143333163035
oct23304206445167
94640135531528
101332012010103
114739a3066195
121961a016375b
13987ba280358
1448680cd7555
15249ae4d5338
hex136221a4a77

1332012010103 has 4 divisors (see below), whose sum is σ = 1332070791960. Its totient is φ = 1331953228248.

The previous prime is 1332012010097. The next prime is 1332012010177. The reversal of 1332012010103 is 3010102102331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1332012010103 - 210 = 1332012009079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332012010193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29356925 + ... + 29402262.

It is an arithmetic number, because the mean of its divisors is an integer number (333017697990).

Almost surely, 21332012010103 is an apocalyptic number.

1332012010103 is a deficient number, since it is larger than the sum of its proper divisors (58781857).

1332012010103 is an equidigital number, since it uses as much as digits as its factorization.

1332012010103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58781856.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1332012010103 its reverse (3010102102331), we get a palindrome (4342114112434).

The spelling of 1332012010103 in words is "one trillion, three hundred thirty-two billion, twelve million, ten thousand, one hundred three".

Divisors: 1 22669 58759187 1332012010103