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133201223101 = 175975725539
BaseRepresentation
bin111110000001101101…
…0010101110110111101
3110201211000121020011101
41330003122111312331
54140244003114401
6141105232253101
712423564500212
oct1740332256675
9421730536141
10133201223101
1151543688461
12219949a1191
13c73a180c9b
1466386d1b09
1536e8e04101
hex1f03695dbd

133201223101 has 4 divisors (see below), whose sum is σ = 133276950400. Its totient is φ = 133125495804.

The previous prime is 133201223093. The next prime is 133201223117. The reversal of 133201223101 is 101322102331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133201223101 - 23 = 133201223093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133201223171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37861011 + ... + 37864528.

It is an arithmetic number, because the mean of its divisors is an integer number (33319237600).

Almost surely, 2133201223101 is an apocalyptic number.

It is an amenable number.

133201223101 is a deficient number, since it is larger than the sum of its proper divisors (75727299).

133201223101 is an equidigital number, since it uses as much as digits as its factorization.

133201223101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75727298.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 133201223101 its reverse (101322102331), we get a palindrome (234523325432).

The spelling of 133201223101 in words is "one hundred thirty-three billion, two hundred one million, two hundred twenty-three thousand, one hundred one".

Divisors: 1 1759 75725539 133201223101